a screw gauge has200 equal divisions marked along the circumerence o the disc and one full rotation o the disc advances on the main scale by 0.05 cm.the least count of the screw gauge is...?

Dear Blessy,

Least count of screw gauge=pitch / total no of div in head scale
pitch = (distance move along the pitch scale when a fixed no of rotations are given to head scale) / no of rotations

Best Of luck

Plz Approve the answer...!!!!

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