Chetan Mandayam Nayakar
Last Activity: 13 Years ago
d2x/dt2 =-a(dx/dt)^2, dx/dt= ±(1/a)d2x/dt2, distance covered has meaning for positive values only,thus dx/dt=-d2x/dt2
d2x/dt2 +dx/dt=0,characteristic equation is m^2+m=0,m(m+1)=0,x=c1+c2e-t, two initial values are required, initial position=c1+c2=0(for the sake of simplicity and without loss of generality),dx/dt=u=-c2, at t=0