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assuming that mass M of the largest stone that can be moved by a flowing river depends 'v' velocity,densityof water and g acc. due to gravity.show that M varies with 6th power of velocity of flow.... assuming that mass M of the largest stone that can be moved by a flowing river depends 'v' velocity,densityof water and g acc. due to gravity.show that M varies with 6th power of velocity of flow....
assuming that mass M of the largest stone that can be moved by a flowing river depends 'v' velocity,densityof water and g acc. due to gravity.show that M varies with 6th power of velocity of flow....
M -> V, d (density) and g Let M (proportional to) Vadbgc Now Hence M = k Vadbgc where k is constant of proportionality [M] = [V]a[d]b[g]c M1L0T0 = (L1T-1)a(M1L-3)b(L1T-2)c M1L0T0 = Mb La - 3b + c T-a - 2c Comparing the powers, b = 1 a - 3b + c = 0 Hence, a - 3(1) + c = 0 a + c = 3 ...........1 -a - 2c = 0 ............2 Solving equations 1 and 2, a + c = 3 -a - 2c = 0 --------------- -c = 3 Hence, c = - 3. Substituting c = -3 in equation 1, we get a = 6. Thus, M = k V6dg hence, it can be said that M varies with 6th power of velocity. Hint: In any type of problems of dimensional analysis where it is given that This quantity depends on so and so... solve by this method always. It would be easier.
M -> V, d (density) and g
Let M (proportional to) Vadbgc
Now Hence M = k Vadbgc where k is constant of proportionality
[M] = [V]a[d]b[g]c
M1L0T0 = (L1T-1)a(M1L-3)b(L1T-2)c
M1L0T0 = Mb La - 3b + c T-a - 2c
Comparing the powers,
b = 1
a - 3b + c = 0
Hence,
a - 3(1) + c = 0
a + c = 3 ...........1
-a - 2c = 0 ............2
Solving equations 1 and 2,
a + c = 3
-a - 2c = 0
---------------
-c = 3
Hence, c = - 3.
Substituting c = -3 in equation 1, we get a = 6.
Thus, M = k V6dg
hence, it can be said that M varies with 6th power of velocity.
Hint: In any type of problems of dimensional analysis where it is given that This quantity depends on so and so... solve by this method always. It would be easier.
M is directly proportional to vˆx M is directly proportional to dˆy M is directly proportional to gˆz m=k*v^x*d^y*g^z m=(l*t^-1)^x*(m*l)^y*(lt^-2)^z y=1 -x-2*z=0 z=-x/2 x-3*y-x/2=0 x=6 m=v^6 -3
M is directly proportional to vˆx
M is directly proportional to dˆy
M is directly proportional to gˆz
m=k*v^x*d^y*g^z
m=(l*t^-1)^x*(m*l)^y*(lt^-2)^z
y=1
-x-2*z=0
z=-x/2
x-3*y-x/2=0
x=6
m=v^6
-3
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M is directly proportional to vˆxM is directly proportional to dˆyM is directly proportional to gˆzm=k*v^x*d^y*g^zm=(l*t^-1)^x*(m*l)^y*(lt^-2)^zy=1-x-2*z=0z=-x/2x-3*y-x/2=0x=6m=v^6-3
Dear student,Please find the attached answer to this question below. Let M (proportional to) VadbgcNow Hence M = k Vadbgc where k is constant of proportionality[M] = [V]a[d]b[g]cM1L0T0 = (L1T-1)a(M1L-3)b(L1T-2)cM1L0T0 = Mb La - 3b + c T-a - 2cComparing the powers, b = 1a - 3b + c = 0Hence, a - 3(1) + c = 0a + c = 3 ...........1-a - 2c = 0 ............2 Solving equations 1 and 2,a + c = 3-a - 2c = 0--------------- -c = 3Hence, c = - 3.Substituting c = -3 in equation 1, we get a = 6.Thus, M = k V6dghence, it can be said that M varies with 6th power of velocity. Hope it helps.Thanks and regards,Kushagra
Hope it helps.
Thanks and regards,
Kushagra
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