Given M1=300g , M2=600g
The System is released from rest. After 2 seconds the larger mass (M2) is stopped. Find the time elapsed before the string is taut again ??
The Given Answer is 2/3 seconds...
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Mayank Jain , 14 Years ago
Grade 11
General Physics> HC Verma Q help !!!...
3 Answers
Sanjeev Malik IIT BHU
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Approved Last Activity: 14 Years ago
Mayank Jain
Thanks a lot!!!
Especially for the links to the solutions !!!
suryapratap babar
hey ..,i am getting a answer 1/3 secs..
at t=2s:
V300g=20/3 m/s working:
v600g = 0 m/s 6 - T = 0.6a
3 - T=0.3a
at t = "when the string will get taut"the speed of both the blocks will be same....
therefore:
20/3 - gt = 0 + gt
so, t = 1/3 s
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