a river flows south east at 10 km/hr and a boat flows upon it with its bow pointed in the direction of travel.a man walks upon the deck at 2 km/hr in a diection to the right and perpendicular to the direction of the boat movement. calculate the absolute velocity of the man.

Question

Shubham Patel · Answer

square root of 2 2 + 10 2 ans- 10.2

Shikhar Srivastava · Answer

Let A and B be the vectors perpendicular to each other.

Magnitude of A = 10 kmph

Magnitude of B = 2 kmph

Angle=90

Therefore resultant velocity = sqrt(A²+B²+2ABcos(theta))

cos 90^o = 0

Puttin' the values we get : sqrt104 = 10.19 kmph (approx).

Ans : 10.198 kmph

Hope it helps. Good Luck!

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a river flows south east at 10 km/hr and a boat flows upon it with its bow pointed in the direction of travel.a man walks upon the deck at 2 km/hr in a diection to the right and perpendicular to the direction of the boat movement. calculate the absolute velocity of the man.

a river flows south east at 10 km/hr and a boat flows upon it with its bow pointed in the direction of travel.a man walks upon the deck at 2 km/hr in a diection to the right and perpendicular to the direction of the boat movement. calculate the absolute velocity of the man.

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