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a river flows south east at 10 km/hr and a boat flows upon it with its bow pointed in the direction of travel.a man walks upon the deck at 2 km/hr in a diection to the right and perpendicular to the direction of the boat movement. calculate the absolute velocity of the man.
square root of 22 + 102
ans- 10.2
Let A and B be the vectors perpendicular to each other.
Magnitude of A = 10 kmph
Magnitude of B = 2 kmph
Angle=90
Therefore resultant velocity = sqrt(A2+B2+2ABcos(theta))
cos 90o = 0
Puttin' the values we get : sqrt104 = 10.19 kmph (approx).
Ans : 10.198 kmph
Hope it helps. Good Luck!
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