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N=mv2/r sinθ + mgcos?
mgsinθ ~ mv2/r cosθ = μN
(Difference symbol because if centrifugal greater then friction stops skid outward
where as if component of weight greater then friction stops slip inwards)
Solve above 2 equation 2 get:
V2/gr=(tan?θ-μ)/(1+μtanθ) or (tanθ+μ)/(1-μtanθ)
Put value of g,r,μ,tanθ=362/rg
v=4.082m/s or 15m/s
multiply by 18/5 to get kph
v=14.7kph or 54 kph
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