General Physics

square root of-

5^2 + 5^2 + 255*cos60 (5^2 means five square)

= 25cos30

how did this come, espacially 2 and cos30???????

Sameer Ahmed

15 Years agoGrade

3 Answers

Sanjeev Malik IIT BHU

15 Years ago

5²+5²+2*5²*1/2 (cos60=1/2) = 3*5²

its square root =5*square root(3)

now,

2*5*cos30=2*5*root(3)/2 (cos30=root(3)/2) = 5*root(3)

hence both are equal

athresh karanam

15 Years ago

cos60=1/2.so the given expression becomes

sq. root of 5²⁺5²+5*5=5*3^1/2=2*5*3^1/2=2*5*cos30..........(because cos30=3^1/2/2)

Aman Ahmad

5 Years ago

I wanted to know the answer too so I researched I know this is from Concept Of Physics 1 Chapter 2, So If we modify the formula sqrt A^2 +B^2+2AB Cos’theta’ for A=B we get 2Acos’theta’/2 and if we put the values in it we get 2x5cos30’degree’ where A=B.

I hope you get the answer.

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square root of- 5^2 + 5^2 + 2*5*5*cos60 (5^2 means five square) = 2*5*cos30 how did this come, espacially 2 and cos30???????

Sameer Ahmed

3 Answers

Sanjeev Malik IIT BHU

athresh karanam

Aman Ahmad

Other Related Questions on general physics

In viewing through a magnifying glass, one usually positions one's eyes very close to the lens. Does angular magnification change if the eye is moved back?

moment of inertia of a equilateral triangle about an axis passing through centre and perppendicular to the plane

. Because of the rotation of the earth, a plumb bob may not hang exactly along the direction ofthe earth’s gravitational pull (its weight) but deviates slightly from this direction. Calculate thedeviation (a) at 40 latitude, (b) at the poles, and (c) at the equator

A block is kept on x-y plane at a point (2m,3m). It is pushed with a force of magnitude 10 Ntowards point (5m,7m). The force can be represented as?

square root of-

5^2 + 5^2 + 255*cos60 (5^2 means five square)

= 25cos30

how did this come, espacially 2 and cos30???????

. Because of the rotation of the earth, a plumb bob may not hang exactly along the direction of
the earth’s gravitational pull (its weight) but deviates slightly from this direction. Calculate the
deviation (a) at 40 latitude, (b) at the poles, and (c) at the equator