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Starting from the origin,a body oscillates simple harmonically with a period of 2sec.After what time will it's kinetic energy be 75% of the total energy...............
Pls explain......
Hey Vishwjit,
we can do this sum as follows:
TE of an SHM is given as 1/2m(wA)^2
K.E for any SHM can be written as 1/2 m(wA)^2 cos^2(wt). even if u dont know this dont worry, u can easily generalise this from the energy of spring-mass system.
so for 75% KE,
3/4 * 1/2 m(wA)^2=1/2 m(wA)^2 cos^2(wt)
=> ((3)^1/2)/2=cos(wt)
we get , wt = pi / 6
w=2 pi/T
t=T/12 = 1/6 seconds.
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