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If the Bernoulli's equation may be written as P + 1/2 p v^2 + hpg = k (constant) where P is pressure, p is density, v is velocity and h is height, find out unit and dimensional formula for k/pv^2.
the constant k(total head) has dimensions of pressure head i.e., N/m2 with dim. formula ML-1T-2 so unit and dimensional formula for k/pv^2 is Dimensionless(no units) and formula is M0L0T0
the constant k(total head) has dimensions of pressure head i.e., N/m2 with dim. formula ML-1T-2
so unit and dimensional formula for k/pv^2 is Dimensionless(no units) and formula is M0L0T0
pv^2 is having the same dimention as the constant k because we kno that for two physical terms to be summable they should have same dimentions,hence all terms on left hand side have same dimentions.Also dimention of left hand side of any physical equation must have same dimention as the right hand side ,hence constant k have same dimentions as the terms "P", P v^2 and hpg. hence the term k/pv^2 is dimentionless!!!=> M^0L^0T^0.
pv^2 is having the same dimention as the constant k because we kno that for two physical terms to be summable they should have same dimentions,hence all terms on left hand side have same dimentions.Also dimention of left hand side of any physical equation must have same dimention as the right hand side ,hence constant k have same dimentions as the terms "P", P v^2 and hpg.
hence the term k/pv^2 is dimentionless!!!=> M^0L^0T^0.
Hi For the statement to be dimensionally correct, every term should have the same units. This means P, (pv^2)/2 , hpg and k should all have same units. Hence, the term k/(pv^2) should be dimensionless.
Hi
For the statement to be dimensionally correct, every term should have the same units. This means P, (pv^2)/2 , hpg and k should all have same units. Hence, the term k/(pv^2) should be dimensionless.
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