Ramesh V
Last Activity: 15 Years ago
F = alpha (symbol)/ ((root) beta + d^2
so dimensions of root(beta) should be same as d2
dimensions of root(beta) are m2 and that of beta are m4 i.e., L4
dimensions of alpha is same as F.d2 i.e., N-m2
dimensions of alpha.beta are N-m6 i.e., ML7T-2