Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
If dy/dx = x^2 + 2, then find the value of y in terms of x. It is given that initially, x = 0 and y = 3.
Hi dy/dx = x^2 + 2 integrating both sides w.r.t x, we get each term as follows: Integration of dy/dx = y + a x^2 = (x^3)/3 + b 2 = 2x + c (a,b and c are constants of integration) Now, combining the terms and taking a,b and c on one side of equation and replacing the resulting constant as Z we get: y= (x^3)/3 + 2x + Z But we are given that y=3 when x=0 putting these values in above equation: 3=0 + 0 + Z Z = 3 Hence, we get our answer as : y= (x^3)/3 + 2x + 3
Hi
dy/dx = x^2 + 2 integrating both sides w.r.t x, we get each term as follows:
Integration of dy/dx = y + a x^2 = (x^3)/3 + b 2 = 2x + c (a,b and c are constants of integration)
Now, combining the terms and taking a,b and c on one side of equation and replacing the resulting constant as Z we get:
y= (x^3)/3 + 2x + Z
But we are given that y=3 when x=0 putting these values in above equation:
3=0 + 0 + Z Z = 3
Hence, we get our answer as : y= (x^3)/3 + 2x + 3
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -