if the kinetic energy of a body is increased by 100% ,then the change in momentum of the body is: pls. Explain.

if momentum inc to 100% then ke inc to 200% as we know ke=1/2mv.v and mv =momentumbecause momentum=2k.e

300 percent

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as we know the relation b/w kinetic energy & momentum as KINETIC ENERGY=P²/2M,

WHERE,,, p=momentum

now substitute in the relation u will get the answer as 300 percent

As KE incr. 100%, it bcms 2 times.

As KE direct. prop. to v², so v bcms √2 times.

As v direct. prop. to p, so p bcms √2 times, so change in p = √2E - E / E Χ 100

                                                                                  = 100(√2 - 1) %

Let k1 be the initial kinetic energy,k2 be the final kinetic energy.

let p1 be intial momentum & p2 be final momentum.

acc. to question,

k2=k1+100%k1

k2=k1+k1=2k1

1\2(mV2)²=2(1\2mV1²)

V2=√2V1

on mutiplying by mass m,

mV2=√2mV1

p2=√2p1.         now,

Δp=p2-p1             =>p1(√2-1)

%age of change in momentum=100(Δp\p1)

                                              =(1.414-1)100

                                              =41.4%

I Hope u understand