two bodies of different masses ma and mb are dropped from two different heights a and b.the ratio of times taken by the two bodies to drop through these distance is:

mass of 'A' is M_a

mass of 'B' is M_b

both of them undergo an accelaration of 'g' as it is falling from a height

initial velocity of both is zero as it is dropped from rest.

From 2nd equation of motion.

S = 1/2 a t²                      [ since u = 0 , it is not taken. ]

a = 1/2g t₁²

b = 1/2g t₂²

a/b = t₁² / t₂²

t₁ / t₂ = √a/b

this the the ratio of times taken by M_a and M_b

Please approve