Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

two bodies of different masses ma and mb are dropped from two different heights a and b.the ratio of times taken by the two bodies to drop through these distance is:

two bodies of different masses ma and mb are dropped from two different heights a and b.the ratio of times taken by the two bodies to drop through these distance is:

Grade:12

2 Answers

Sudheesh Singanamalla
114 Points
10 years ago

mass of 'A' is Ma

mass of 'B' is Mb

both of them undergo an accelaration of 'g' as it is falling from a height

initial velocity of both is zero as it is dropped from rest.

From 2nd equation of motion.

S = 1/2 a t2                      [ since u = 0 , it is not taken. ]

a = 1/2g t12

b = 1/2g t22

a/b = t12 / t22

t1 / t2 = √a/b

 

this the the ratio of times taken by Ma and Mb

 

Please approve

ankit singh
askIITians Faculty 614 Points
one year ago
for First object we get :

h1= gT1²/2
⇒T1=√2h1/g

For second object we get h2=gT2²/2
⇒T2=√2h2/g
T1/T2 =√h1/h2
But here h1= a and h2 =b
so, T1/T2=√a/b

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free