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q.1 A horozontal platform vibrates up & down with a SHM of frequency 2 / pai HZ. find the max permissible amplitude so that an object kept on the platform remain in contact with platform.
x = A sinwt
a (accleration) = -Aw2sinwt
maximum accleration = -w2A
when this accleration is just equal to accleration due to gravity then particle is about to leave
the surface ...if accleration is more than this value then it will loose the contact
w2A = g
A = g/W2 ....................1
w = 2pif
f = 2/pi so
w = 4radiansec-1
A = g/42 = 10/16 = 0.625m (g = 10m/s2)
approve if u like my ans
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