q.1 A horozontal platform vibrates up & down with a SHM of frequency 2 / pai HZ. find the max permissible amplitude so that an object kept on the platform remain in contact with platform.

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vikas askiitian expert · Answer

x = A sinwt a (accleration) = -Aw 2 sinwt maximum accleration = -w 2 A when this accleration is just equal to accleration due to gravity then particle is about to leave the surface ...if accleration is more than this value then it will loose the contact w 2 A = g A = g/W 2 ....................1 w = 2pif f = 2/pi so w = 4radiansec -1 A = g/4 2 = 10/16 = 0.625m (g = 10m/s 2 ) approve if u like my ans

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q.1 A horozontal platform vibrates up & down with a SHM of frequency 2 / pai HZ. find the max permissible amplitude so that an object kept on the platform remain in contact with platform.

q.1 A horozontal platform vibrates up & down with a SHM of frequency 2 / pai HZ. find the max permissible amplitude so that an object kept on the platform remain in contact with platform.

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