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q.1 A horozontal platform vibrates up & down with a SHM of frequency 2 / pai  HZ. find the max permissible amplitude so that an object kept on the platform remain in contact with platform.

8 years ago

Answers : (1)

vikas askiitian expert
509 Points
							

x = A sinwt

a (accleration) = -Aw2sinwt

maximum accleration = -w2A

when this accleration is just equal to accleration due to gravity then particle is about to leave

the surface ...if accleration is more than this value then it will loose the contact

w2A = g

A = g/W2               ....................1

w = 2pif

f = 2/pi so

w = 4radiansec-1

A = g/42 = 10/16 = 0.625m                            (g = 10m/s2)

 

approve if u like my ans

8 years ago
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