if the angle between the vectors A and B is @ ,the value of the product (B x A).A is equal to(a) BA^2sin@ (b) BA^2cos@ (c) BA^2cos@sin@ (d) zeroi wanted the solution alsowaiting for ur reply@ as theta^2 as to the power of

let BxA = R

BxA is a vector which is perpendicular to both B & A ...

(BxA).A = R.A

R perpendicular to A so dot product will be 0 ...            (dot product of any two perpendicular vectors is 0)

so , (BxA).A =0

opton d) is correct

Approved

thanks bro!!!!!!!!!!!!!!!!!!!!!!!!!

Dear Student,
Please find below the solution to your problem.

let BxA = R
BxA is a vector which is perpendicular to both B & A ...
(BxA).A = R.A
R perpendicular to A so dot product will be 0 ... (dot product of any two perpendicular vectors is 0)
so , (BxA).A =0

Thanks and Regards