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if the angle between the vectors A and B is @ ,the value of the product (B x A).A is equal to(a) BA^2sin@   (b) BA^2cos@   (c) BA^2cos@sin@  (d) zeroi wanted the solution alsowaiting for ur reply@ as theta^2 as to the power of

10 years ago

let BxA = R

BxA is a vector which is perpendicular to both B & A ...

(BxA).A = R.A

R perpendicular to A so dot product will be 0 ...            (dot product of any two perpendicular vectors is 0)

so , (BxA).A =0

opton d) is correct

one year ago
Dear Student,

let BxA = R
BxA is a vector which is perpendicular to both B & A ...
(BxA).A = R.A
R perpendicular to A so dot product will be 0 ... (dot product of any two perpendicular vectors is 0)
so , (BxA).A =0

Thanks and Regards