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The magnitude of vectorA - vectorB = A+B
Then find the angle between vectorA and vectorB?
waiting for reply
magnitude[A-B] = magnitude[A+B]
squaring both sides
A2 + B2 - 2A.B = A2 + B2 + 2A.B
A.B = 0
A.B = ABCOS@ so
cos@ = 0
@ = pi/2
therefore angel bw A,B is 90o ...
approve if u like my ans
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