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WHEN A PLANE MIRRORIS PLACED HORIZONTALLY ON LEVEL GROUND AT A DISTANCE OF 60M FROM FOOT OF TOWER THE TOP OF THE TOWER AND ITS IMAGE IN MIRROR SUBSTENDS AN ANGLE OF 90 DEGREES .Find height of tower 30m 60m 90m 120m
mirror is placed on horizontal ground .... incidend ray & refracted ray are at 90o ... angle substended by both rays with normal(verticle axis) of plane is same , so let this angle be @ then @ + @ = 90 @ = 45o now using tan@ = h/d tan45 = h/d h = d height of tower is same 60m...... option b is correct
mirror is placed on horizontal ground ....
incidend ray & refracted ray are at 90o ...
angle substended by both rays with normal(verticle axis) of plane is same , so let this
angle be @ then
@ + @ = 90
@ = 45o
now using tan@ = h/d
tan45 = h/d
h = d
height of tower is same 60m......
option b is correct
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