MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 10
        atable with flat top and mass 10 kg is kept on a fl;at horizontal ground. a block of mass m=2 kg rests on the top of the table. a force F is applied at an angle of 30 degree and the block moves with an acceleration of root3 m/s.

1)find force exerted by block on eart
3)find force exerted by table on block
2)find force exerted by ground on table.
4)find net force acting on block
8 years ago

Answers : (1)

vikas askiitian expert
509 Points
							

horizontal component force will provide accleration ...

Fcos30 = 31/2F/2  = FH = force in horizontal direction

ma = 31/2F/2

m=2kg , a = 31/2 so

F = 4N

net force acting in verticle direction = mg+Fsin30 = 22N

 

normal force bw table & block = 22N

 

normal force bw ground & table = 22+weight of table

                                            =22+100 = 122N

 

net force acting on block = [ N2 + (FH)2 ]1/2 

N is normal force bw block & table , FH is horizontal comp of applied force ....

                                   = [12 + 222]1/2 = 22.3N

8 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 18 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details