atable with flat top and mass 10 kg is kept on a fl;at horizontal ground. a block of mass m=2 kg rests on the top of the table. a force F is applied at an angle of 30 degree and the block moves with an acceleration of root3 m/s. 1)find force exerted by block on eart 3)find force exerted by table on block 2)find force exerted by ground on table. 4)find net force acting on block

horizontal component force will provide accleration ...

Fcos30 = 3^1/2F/2  = F_H = force in horizontal direction

ma = 3^1/2F/2

m=2kg , a = 3^1/2 so

F = 4N

net force acting in verticle direction = mg+Fsin30 = 22N

normal force bw table & block = 22N

normal force bw ground & table = 22+weight of table

                                            =22+100 = 122N

net force acting on block = [ N² + (F_H)² ]^1/2 

N is normal force bw block & table , F_H is horizontal comp of applied force ....

                                   = [12 + 22²]^1/2 = 22.3N