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A stone is thrown with an initial speed of 4.9m/s from a bridge in vertically upward direction .It falls in ground in 2 sec.find height of bridge.Please explain with diagram
dear amit , u is given = 4.9 , total time of flight = 2sec applying , S = ut + at2/2 , S = H = ? , a=-g , u=+4.9m/s (upward) putting these in above eq H = 4.9*2 - 9.8(4)/2 = 9.8m
dear amit ,
u is given = 4.9 , total time of flight = 2sec
applying , S = ut + at2/2 ,
S = H = ? , a=-g , u=+4.9m/s (upward)
putting these in above eq
H = 4.9*2 - 9.8(4)/2 = 9.8m
a ball dropped downwards . After 1 second another ball is dropped downwards from the same point. What is the distance between them after 3 seconds
A body thrown after 1 second are in the ratio1:3 so there difference after 3 second will be 27-9=18therefore answer is 18
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