Join now for JEE/NEET and also prepare for Boards Learn Science & Maths Concepts for JEE, NEET, CBSE @ Rs. 99! Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
When an object moves through a viscous medium such as air or water, the object experiences a velocity dependent retarding force. This retarding force may be proportional to the first (linear) or the second power (quadratic) of the velocity (a case often studied in classical mechanics).
We will model the movement of an object moving through a viscous medium with the following differential equation:
m.dV/dt = mg - kV where m is the mass of the object,
k is a scaling or proportionality factor that accounts for the area experiencing the viscous force, dimensional formula is MT-1
V is the velocity,
=> integral of [dV/(mg - kV)] limits from 1 to 0.63Vt = integral of [ dt/m ] limits from 0 to T(time constant)
on solving gives T=(m/k)*ln[mg / (mg - 0.63Vt)]
where its dimesnion formula is T
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !