Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A body is thrown up wuth initial velocity 'u' .and reaches height 'h' To reach double height it must be projected with initial velocity of-

A body is thrown up wuth initial velocity 'u' .and reaches height 'h'


To reach double height it must be projected with initial velocity of-

Grade:9

6 Answers

vikas askiitian expert
509 Points
10 years ago

 if the particle is projected with velocity u then at maximum height its velocity becomes 0

 we have ,

                   V2 = U2 - 2gHmax

                  U2 = 2gHmax                or 

                U2 directly  proportional to Hmax     

            (Ui)2 / (Uf)2 = (Hmax)i/(Hmax)f

Ui = u , Uf=? , (Hmax)i = h , (Hmax)f = 2h

after substituting these

        Uf = (sqrt2)u        ans

 

Fawz Naim
37 Points
10 years ago

the height attained by the body is h therefore applying third equation of motion

v^2=u^2-2gh

at height h final velocity is zero

u^2=2gh

u=square root(2gh) ....1

now height attained by the body is 2h

therefore putting 2h in place of h

the equation comes to be

u'^2=2g(2h)

u'= square root(2*2gh)

but square root 2gh=u

therefore u'=u*square root(2)

 

nikhil arora
54 Points
10 years ago

it is given that 'h' height is attained by a body and its velocity is u...

writing eqn of motion...

v(sqr)-u(sqr)=2as

putting values....

v=0,u=u,and a=-g(coz g is in downward direction), s=h

-u(sqr)=2(-g)h

u(sqr)=2gh

so to get height of 2h u should be sqrroot(2) to satisfy above eqn

 

answer is sqrroot(2)

Ajay Kumar
34 Points
10 years ago

root 2 times the original velocity

Aniket Patra
48 Points
10 years ago

It is sqrt 2 times u.

surendranadh
8 Points
6 years ago
sqrt of usqr+2gh 
derivation please

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free