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if in atwood machine m1=1.30kg and m2=2.80kg at t=o.
m1 starts losing the mass at a rate of .200kg/s due to leakage.at what rate does the acc. of the container changes at t=0sec and t=3 sec.
when dos the acc. reach max. value
what is an atwood machine.
dm1/dt = -0.2kg/s ( given)
dm1 = -0.2dt
integrating both sides
m1 = -0.2t + c
at t=0 , m1=1.3
therefore , c=1.3
now , m1 = 1.3 - 0.2t ...............1 (mass of m1 at any time)
now accleration (a)= g(m2-m1)/(m2+m1)
a = g{m2 - (1.3-0.2t)}/{m2+(1.3-0.2t)} (putting m1 from eq 1)
a =g(1.5+0.2t)/(4.1-0.2t) ...................2 (after putting value of m2)
da/dt = g(1.12)/{4.1-0.2t)2 ................3
at t=0 ,
da/dt = 0.652m/s2
at t=3
da/dt = 0.896m/s2
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