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A Body of mass m is slowly pulled up the hill by a force F which at a point was directed along the tangent of the trajectory. All surfaces are smooth. Find the work performed by this force.
applying work energy theorem change in kinetic energy = work done by all forces = Wmg + Wext work by gravity = -mgh (-ve sign is because work is done against gravity) work by F is Wext change in kinetic energy = 0 so Wext - mgh = 0 Wext = mgh so work by force F is mgh , this work will not depend on the angle of incline ......
applying work energy theorem
change in kinetic energy = work done by all forces
= Wmg + Wext
work by gravity = -mgh (-ve sign is because work is done against gravity)
work by F is Wext
change in kinetic energy = 0
so
Wext - mgh = 0
Wext = mgh
so work by force F is mgh , this work will not depend on the angle of incline ......
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