Acc to archimedes principle, loss of weight of a body in a liquid is equal to the wt of the liquid displaced

i.e. W₂ -W₁ = Vpg

But I read the synopsis in one of the books that when a body is dipped in a liqid, then it's wt in fluid = Vpg.

Which of the two is right?

Also Vag(1-p/a) = what ? Is it the change in fluid or the wt of the fluid in the liquid. here a= density of the body

p = density of the liquid.

What is the apparent weight of the body numericlly equal to?

I got confused due to reading contradictory statements in different books. Please help me solve this dilemma.

deeksha sharma

15 Years agoGrade 11