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If g e and g m are the accelerations due to gravity on the surfaces of the earth and the moon respectively and if Millikan's oil drop experiment could be performed on the two surfaces, one will find the ratio (electronic charge on the moon) / (electronic charge on the earth) to be :- (A) 1 (B) 0 (C) g e /g m (D) g m /g e Please explain.

If ge and gm are the accelerations due to gravity on the surfaces of the earth and the moon respectively and if Millikan's oil drop experiment could be performed on the two surfaces, one will find the ratio 


(electronic charge on the moon) / (electronic charge on the earth) to be :-


(A) 1


(B) 0


(C) ge/gm


(D) gm/ge


Please explain.

Grade:12

2 Answers

vikas askiitian expert
509 Points
11 years ago

let the magnitude of electric field used is E...

magnitude of charge at moon and earth are qm & qe respectively....

at moon

              Eqm=mgm ..................1                      

 at earth

            Eqe=mge ..................2

balancing the gravitational force by electric force

dividing 1 and 2

        qm/qe=gm/ge ........

option d is correct

AnumulavishnU
15 Points
3 years ago
Since electronic charge is universal (e = charge of electron) answer is '1'...........................................................

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