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If g e and g m are the accelerations due to gravity on the surfaces of the earth and the moon respectively and if Millikan's oil drop experiment could be performed on the two surfaces, one will find the ratio (electronic charge on the moon) / (electronic charge on the earth) to be :- (A) 1 (B) 0 (C) g e /g m (D) g m /g e Please explain.
let the magnitude of electric field used is E... magnitude of charge at moon and earth are qm & qe respectively.... at moon Eqm=mgm ..................1 at earth Eqe=mge ..................2 balancing the gravitational force by electric force dividing 1 and 2 qm/qe=gm/ge ........ option d is correct
let the magnitude of electric field used is E...
magnitude of charge at moon and earth are qm & qe respectively....
at moon
Eqm=mgm ..................1
at earth
Eqe=mge ..................2
balancing the gravitational force by electric force
dividing 1 and 2
qm/qe=gm/ge ........
option d is correct
Since electronic charge is universal (e = charge of electron) answer is '1'...........................................................
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