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a 0.25 kg block of cheese lies on floor of 900 kg through a distance d1=2.40m and d2=10.5m
(a) through d, normal force on the block from floor is Fn =3N. how much work is done on lift by a force from cable.ANS-25.9
(b) through d2 if work done by lift is 92.61 kg , what is magnitude of Fn. ANS-2.45
given the normal reaction on floor is 3N
SO m(g+a)=3 m is mass of cheese
a =2 m/s2
we know work done =F.S
= mas ( a=g+a
=900.25x 12x 2.4
=25.9 kj =12)
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