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a 0.25 kg block of cheese lies on floor of 900 kg through a distance d1=2.40m and d2=10.5m

(a) through d, normal force on the block from floor is Fn =3N. how much work is done on lift by a force from cable.ANS-25.9

(b) through d2 if work done by lift is 92.61 kg , what is magnitude of Fn. ANS-2.45

pranay -askiitians expert , 15 Years ago
Grade 12
anser 1 Answers
bhargav teja

given the normal reaction on floor is 3N

SO m(g+a)=3           m is mass of cheese

 a =2 m/s2

we know work done =F.S

                            = mas                                  ( a=g+a

                            =900.25x 12x 2.4

                            =25.9 kj                                                =12)   

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