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A balloon ascends with a uniform acceleration of 981 /8 cm/s2, at the end of half a minute a body is released from it, find the time that elapses before the body reaches the ground. [g = 9.81]
accelration of baloon is 981/8 cm/sec^2=9.8/8 m/sec^2
after half minute velocity of baloon is v=u+at
=9.8*30/8 m/sec (u=0)
total height attained by baloon is H=ut+at^2/2
=450*9.8/8 m
at this time the particle is dropped so its velocity will be same as of baloon in upward direction....
velocity of paticle is u=9.8*30/8 m/sec
now using s=ut+at^2/2 for particle
s=-H , u=9.8*30/8 ,g=-9.8,after putting these values we get a quadratic in t
2t^2 -15t-225=0
t=15,-7.5 sec
t=15 is required ans
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