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charges of +(10/3)*1/10000000 are placed at each of the
four corners of a square of side 8cm .the potential at the intersection of the diagonals is.
PLEASE SOLVE THIS QUESTION.
Dear sunny shah,
V(r) = (1/4 π ε)* (q1/r1+ q2/r2+ q3/r3+ q4/r4) = (1/4 π ε)* 4*(q/r) = (1/ π ε)* (q/r)
q1=q2=q3=q4=q
r=sqrt(4^2+4^2) because the total lenght of the side is 8cm . the cahrge is at diagonal of the square from the center
r=sqrt(32) cm chane to meter
r=(1/10)*sqrt(32) m
ε= 8.854187817...×10−12 A·s/(V·m) = 8.854187817...×10−12 F/m
q=+(10/3)*1/10000000 = (10/3)* 10^-6
Π=22/7
now u can use the formula and values given above. do it so u can get practice and solve the otherparts
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