shortest method for calculating rangein incined plane
aashit agarwal , 14 Years ago
Grade
1 Answers
Chetan Mandayam Nayakar
Last Activity: 14 Years ago
let angle of projection w.r.t. horizontal be A, y=xtanA - gx2/2u2cos2A =xtanθ, where theta is the angle of inclination of the plane, dividing both sides of the equation by 'x' and simplifying, we get range=(2u2cos2A/g)(tanA -tanθ)
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