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a mass of 4 kg rests on a horizontal plane the plane. the gradually inclined until at an angle 15 with the horizontal, the mass just bugins to slide. what is the cofficient of static friction between the block and the surface?

a mass of 4 kg rests on a horizontal plane the plane. the gradually inclined until at an angle 15 with the horizontal, the mass just bugins to slide. what is the cofficient of static friction between the block and the surface?

Grade:11

3 Answers

gOlU g3n|[0]uS
42 Points
10 years ago

 M = 4 kg

x= theta =  15

Mgsinx = μMgcosx

then find μ = ?  if u find worng ans then tell me

Gokul Joshi AskiitiansExpert-IITK
42 Points
10 years ago

Dear Vinay,

This is called angle of repose. 
http://www.askiitians.com/iit-jee-physics/mechanics/friction-page4.aspx
http://www.askiitians.com/iit-jee-physics/mechanics/friction-page5.aspx

So coefficient of static friction = ms = tan(α) = tan(15°)


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Himani
19 Points
4 years ago
A car of mass 1000 kg travelling at 32 m\s dashes into the rear of a truck of mass 8000 kg moving in the same direction with a velocity of 4 m\s after the collision the car bounces with a velocity of 8 m\s what is the velocity of truck after the impact

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