Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

2 particles one with constant velocity of 50m/s and the other with uniform acceleration of 10m/s 2 start moving simultaneously from the same place in the same direction.They will be at a distance of 125 m from each other after?ans.5(1+root 2)s

2 particles one with constant velocity of 50m/s and the other with uniform acceleration of 10m/s2 start moving simultaneously from the same place in the same direction.They will be at a distance of 125 m from each other after?ans.5(1+root 2)s

Grade:12

1 Answers

Gokul Joshi AskiitiansExpert-IITK
42 Points
11 years ago

Dear Umme,

We can do it by relative motion concepts. From frame of 1st particle, u21 = -50 and a21 = 10.
s21 = 125 = u21 t + 1/2 a21 t2 = -50t + 1/2 10 t2
=> 25 = -10t + t2
Solving: t = 5 + 5 sqrt(2) = 5 (1 + sqrt(2)) seconds



Please feel free to post as many doubts on our discussion forum as you can. If you find any question difficult to understand - post it here and we will get you the answer and detailed  solution very  quickly.

We are all IITians and here to help you in your IIT JEE preparation.All the best.

Regards,
Askiitians Experts,
Gokul  Joshi




Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free