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A stone is thrown upwards with an accelaration of 10 m/sec.sq.If its velocity is 10m/sec, then find the distance and taken to reach the ground.
Please suggest the right method to do it
thanks
Dear Neel
stone will go upwards and at its maximum height its velocity will be zero
apply v2= u2 + 2as
put,v=0, u= 10, a=g=-10 m/s2
s=?
0=100-20*s
it gives s= 5m
it will cover total distance of 2*5=10m (up and down)
for calculation of time use s=ut + 0.5at2
remember s in these equtions is displacment , when stone go up and then come down total displacement will be zero.
s=0, u= 10, a=g=-10
put these values it gives t=2 sec.
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