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Grade: 12

                        

62 number question answer this question Fastly ,,✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️✌️

3 months ago

Answers : (2)

Sanyam Shah
54 Points
							
A and B are the correct answer....
Since x3+ax2-c=0 has three real roots … It implies that it has a maxima and minima as well at x=(-2a/3) and x=0 respectively...
On putting x=(-2a/3) and x=0 in equation f(x)=x3+ax2-c we get (4a3-27c)/27 and (-c) respectively.
Hence for just one solution of f(x)=k, we get k>(4a3-27c)/27 and k
Approve my answer if you like it....
3 months ago
Sanyam Shah
54 Points
							
For more clearity, draw a simple graph of a cubic equation...to understand the problem in a simple manner..
Hope your doubt is cleared ….
Approve my answer if you like it....
 
3 months ago
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