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`        23 no. Question Solve it Plzzzzzzzzz . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . `
one year ago

Vikas TU
9798 Points
```							Given that P + Q + R = 0P + Q = – R squaring both sides we get,|P|^2 + |Q|^2 + 2P.Q = |R|^2|P|^2 + |P|^2 + 2P.Q = 2|P|^2 (Gven |P| = |Q| and |R| = root2*|P|)P.Q = 0Hence the angle between P and Q is 90 degree as their dot product is zero. Angle between Q and R => costhetha = Q.R/(|Q||R|) =>From P + Q + R = 0Q + R = – P|R|^2 + |Q|^2 + 2Q.R = |P|^22|P|^2 + |P|^2 + 2Q.R = |P|^2Q.R = -|P|^2 Hence, costhetha =  -|P|^2/(root2|p|^2) => – 1/root2thetha  = 135 degree Hence a opion is correct.
```
one year ago
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### Course Features

• 18 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions