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1} When a load of 10 kg is hung from the wire, then extension of 2 m is produced. Then work done by restoring force is_____________?

1} When a load of 10 kg is hung from the wire, then extension of 2 m is produced. Then work done by restoring force is_____________?

Grade:11

1 Answers

Arun
25750 Points
5 years ago
F = -kx is the restoring force 

k is the spring constant 

=> load of 10 kg weighs 10g N 

=> 10(9.81) = k(2) => k = 49.05 N/m 

therefore work done = forceₐᵥₑ x displacement in direction of force 

here forceₐᵥₑ(kx/2) and distance moved are oppositely directed 

W =[ -49.05 + 0] *2*2/2 = - 98.1 J 


this work done is stored in the wire as elastic potential energy(½kx²) 

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