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1 For ?dy = 0 and for any given vo find ? so that the range (?dx) is maximum.

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For ?dy = 0 and for any given vo find ? so that the range (?dx) is maximum.

Grade:12

1 Answers

Sher Mohammad IIT Delhi
askIITians Faculty 174 Points
9 years ago
range is maximum for angle of projection=45
so max height of the particle=vo^2*sin^2(theta)/2*g
=vo^2/4g

Sher Mohammad
b.tech iit delhi
faculty, Askiitians

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