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1 For ?dy = 0 and for any given vo find ? so that the range (?dx) is maximum.

him sharma , 11 Years ago
Grade 12
anser 1 Answers
Sher Mohammad

Last Activity: 10 Years ago

range is maximum for angle of projection=45

so max height of the particle=vo^2*sin^2(theta)/2*g
=vo^2/4g

Sher Mohammad
b.tech iit delhi
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