Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

1 For ?dy = 0 and for any given vo find ? so that the range (?dx) is maximum.

1

For ?dy = 0 and for any given vo find ? so that the range (?dx) is maximum.

Grade:12

1 Answers

Sher Mohammad IIT Delhi
askIITians Faculty 174 Points
7 years ago
range is maximum for angle of projection=45
so max height of the particle=vo^2*sin^2(theta)/2*g
=vo^2/4g

Sher Mohammad
b.tech iit delhi
faculty, Askiitians

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free