When a sound wave of frequency 300 Hz passes through a medium, the maximum displacement of a particle of the medium is 0.1 cm. the maximum velocity of the particle is equal to
(a) 60 p cm/s
(b) 30 p cm/s
(c) 30 cm/s
(d) 60 cm/s

Question

Saurabh Koranglekar · Answer

Dear student The answer is option a Regards

Vikas TU · Answer

Frequency of sound wave = 300Hz (Given) Maximum displacement or amplitude of a particle of the medium = 0.1 cm (Given) Maximum velocity = angular frequency × amplitude Angular frequency = 2π × frequency = 2π × 300 rad/s = 600π rad/s Maximum velocity of wave = 600π rad/s × 0.1cm = 600π × 0.1 = 60πcms⁻¹ Thus, the maximum velocity of the particle is equal to 60πcms⁻¹

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When a sound wave of frequency 300 Hz passes through a medium, the maximum displacement of a particle of the medium is 0.1 cm. the maximum velocity of the particle is equal to (a) 60 p cm/s (b) 30 p cm/s (c) 30 cm/s (d) 60 cm/s

When a sound wave of frequency 300 Hz passes through a medium, the maximum displacement of a particle of the medium is 0.1 cm. the maximum velocity of the particle is equal to
(a) 60 p cm/s
(b) 30 p cm/s
(c) 30 cm/s
(d) 60 cm/s

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