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# What is the change in surface energy, when a mercury drop of radius R splits up into 1000 droplets of radius r? (a) 8 pR2T (b) 16 pR2T (c) 24 pR2T (d) 36 pR2T

Arun
25763 Points
one year ago

Surface Energy -

It is defined as the amount of work done in increasing the area of the liquid against surface tension.

-

$n\frac{4}{3}\pi r^{3}=\frac{4}{3}\pi R^{3}$

$nr^{3}=R^{3}$

$=> R=n^{1/3}r$

where n= 10000

After calculeting we get $r=36\rho R^2T$

Vikas TU
14149 Points
one year ago
Surface Energy -
It is defined as the amount of work done in increasing the area of the liquid against surface tension.
where n= 10000
After calculeting we get r=36\rho R^2T