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Dear studentPlease find the link attachedhttps://www.askiitians.com/forums/Engineering-Entrance-Exams/under-the-action-of-load-f1-the-length-of-a-strin_77655.htmRegards
Let dL be the change in length
and L be the Original length
Therefore Y=(f1*L)/(A*dL) for L1
= (f1*L)/A*(L-L1)--------(1)
Y=(f2*L)/(A*dL) forL2
=(f2*L)/A(l-L2)-------(2)
Equating both 1&2
F1/(L-L1)=f2/(L-L2)
=>L=(f1L2-f2L1)/(f1-f2)
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