Vikas TU
Last Activity: 5 Years ago
Length of the wire = 1:2
ΔL=FL/AY, La/Lb = 1/2 (Given)
Since the wires are pulled by the same force and are made up of the same material hence Fa = Fb = FYa = YB = Y
ΔLa/ΔLb = La/πr²a×πr²b/Lb, rA/rB = 2/1
ΔLa/ΔLb = La/Lb×(rB/rA)²
ΔLa/ΔLb = 1/2×(1/2)² = 1/8
ΔLa/ΔLb - 1/8
Thus the increase in the length will be in the ratio 1:8