Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Two points P and Q are maintained at the potentials of 10V and –4V, respectively. The work done in moving 100 electrons from P to Q is ?

Two points P and Q are maintained at the potentials of 10V and –4V, respectively. The work done in moving 100 electrons from P to Q is ?

Grade:11

2 Answers

Arun
25763 Points
11 months ago
potential difference=V=410=14V
 
Charge=q=100e=1.6×1017C
 
Now, potential difference, V=qW
 
W=qV=1.6×1017×(14)
 
W=2.24×1016J
Vikas TU
14149 Points
11 months ago
We know , work done in moving a charge q is given by :
W=q(Vf-Vi)     ......( 1 )
Here :
q = 100e 
Putting all value in equation 1 :
We get :
W=-1.6* 10^{-17}*(-4-10)
W=1.6*14*10^{-17} J
W=2.24 * 10^{-16} J
Therefore , this is the required solution .

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free