Two identical light waves, propagating in the same direction, have a phase difference d. After they superpose the intensity of
the resulting wave will be proportional to
(A) cos d (B) cos (d/2) (C) cos2
(d/2) (D) cos2
d

Question

Saurabh Koranglekar · Answer

Dear student The answer is option c Regards

Vikas TU · Answer

I'=I1+I2+2√(I1*I2)*cos x Given, I1=I2 So, I'=I+I+2Icos x I'=2I(1+cos x) =2I*2(cos (x/2))^2 …..............

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Two identical light waves, propagating in the same direction, have a phase difference d. After they superpose the intensity of the resulting wave will be proportional to (A) cos d (B) cos (d/2) (C) cos2 (d/2) (D) cos2 d

Two identical light waves, propagating in the same direction, have a phase difference d. After they superpose the intensity of
the resulting wave will be proportional to
(A) cos d (B) cos (d/2) (C) cos2
(d/2) (D) cos2
d

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Two identical light waves, propagating in the same direction, have a phase difference d. After they superpose the intensity of the resulting wave will be proportional to (A) cos d (B) cos (d/2) (C) cos2 (d/2) (D) cos2 d

Two identical light waves, propagating in the same direction, have a phase difference d. After they superpose the intensity of the resulting wave will be proportional to (A) cos d (B) cos (d/2) (C) cos2 (d/2) (D) cos2 d

2 Answers

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Two identical light waves, propagating in the same direction, have a phase difference d. After they superpose the intensity of
the resulting wave will be proportional to
(A) cos d (B) cos (d/2) (C) cos2
(d/2) (D) cos2
d