Two closed pipe produces 10 beats per second when emitting their fundamental nodes. If their lengths are in the ratio of 25: 26 their fundamental frequency in Hz are(a) 270, 280(b) 260, 270(c) 260, 250(d) 240, 250
sumit kumar , 10 Years ago
Grade Upto college level
2 Answers
Arun
Last Activity: 4 Years ago
We know that the fundamental frequency of a closed end pipe is given by
f=4Lv
f1=4L1v and f2=4L2v
f2f1=L1L2=2526
⟹f1=2526f2
Now, beat=f1−f2=10
⟹2526f2−f2=10
⟹f2=250Hz
And, f1=2526f2=260Hz
Answer-(C)
Vikas TU
Last Activity: 4 Years ago
Dear student Above ans is not understandable f = v/4L f1 = v/4L1 f2 = v/4L2 f1/f2 = 26/25 f1 - f2 =10 26/25 f2 - f2 = 10 f2 = 250 Hz f1 = 26/25 f2 = 260 Hz
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