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To send 10% of the main current through a moving coil galvanometer of resistance 99 ohm the shunt required is a) 10 ohm b) 9.9 ohm c) 9 ohm d) 11 ohm

To send 10% of the main current through a moving coil galvanometer of resistance 99
ohm the shunt required is

a) 10 ohm b) 9.9 ohm c) 9 ohm d) 11 ohm

Grade:

2 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
576-1141_3.PNG
Vikas TU
14149 Points
one year ago
The shunt required will be 11 ohm.
We know that potential difference across galvanometer is equal to the potential difference across the shunt so we have
igG=(i-ig)S........(1)   where we have
ig is current through galvanometer.
i is main current
G is resistance of galvanometer.
S as resistance of shunt.
Now according to question ig=1/10i G=99 ohm
Substituting values in equation (1) we have;-
(1/10)i*99=(i-i/10)S
(1/10)i*99=(9/10)iS cancelling i and 1/10 both sides we have
99=9S so S=11 ohm
Hence resistance of shunt is 11 ohm.
 
 

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