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To send 10% of the main current through a moving coil galvanometer of resistance 99 ohm the shunt required is a) 10 ohm b) 9.9 ohm c) 9 ohm d) 11 ohm

To send 10% of the main current through a moving coil galvanometer of resistance 99
ohm the shunt required is

a) 10 ohm b) 9.9 ohm c) 9 ohm d) 11 ohm

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2 Answers

Saurabh Koranglekar
askIITians Faculty 10336 Points
2 years ago
576-1141_3.PNG
Vikas TU
14149 Points
2 years ago
The shunt required will be 11 ohm.
We know that potential difference across galvanometer is equal to the potential difference across the shunt so we have
igG=(i-ig)S........(1)   where we have
ig is current through galvanometer.
i is main current
G is resistance of galvanometer.
S as resistance of shunt.
Now according to question ig=1/10i G=99 ohm
Substituting values in equation (1) we have;-
(1/10)i*99=(i-i/10)S
(1/10)i*99=(9/10)iS cancelling i and 1/10 both sides we have
99=9S so S=11 ohm
Hence resistance of shunt is 11 ohm.
 
 

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