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Time taken by a 836 W heater to heat one litre of water from 10dgreeC to 40dgreeC is (A) 50 s (B) 100 s (C) 150 s (D) 200 s

Time taken by a 836 W heater to heat one litre of water from 10dgreeC to 40dgreeC is
(A) 50 s (B) 100 s (C) 150 s (D) 200 s

Grade:12

1 Answers

Rohit Reborn
24 Points
4 years ago
 
heat required by water = heat emitted by heater
i.e     ms/\T = power × time..............(since, heat = power × time)
=>     time = ms/\T / power
=>      time = {1000× 4.186 × (40-10)} / 836.......................... (1 litre = 1kg = 1000 g)
=>      time = 150 sec.

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