Time period of simple pendulum of length l and a place where acceleration due to gravity is g is T. what is the period of a simple pendulum of the same length at a place where the acceleration due to gravity is 1.029 is,
(a) T (b) 1.02 T
(c) 0.99 T (d) 1.01 T
sumit kumar , 11 Years ago
Grade Upto college level
2 Answers
Saurabh Koranglekar
Last Activity: 4 Years ago
Dear student
The Time period = 2pi*(sqrt (l/g))
Now we can calculate the needful
Regards
Vikas TU
Last Activity: 4 Years ago
When acceleration due to gravity (g) is constant, the time period (T) of oscillation of a simple pendulum is directly proportional to the square root of its effective length (L).
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