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Grade Upto college level Engineering Entrance Exams

Time period of simple pendulum of length l and a place where acceleration due to gravity is g is T. what is the period of a simple pendulum of the same length at a place where the acceleration due to gravity is 1.029 is, (a) T (b) 1.02 T (c) 0.99 T (d) 1.01 T

Profile image of sumit kumar
12 Years agoGrade Upto college level
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2 Answers

Profile image of Saurabh Koranglekar
6 Years ago
Dear student

The Time period = 2pi*(sqrt (l/g))

Now we can calculate the needful

Regards
Profile image of Vikas TU
6 Years ago
When acceleration due to gravity (g) is constant, the time period (T) of oscillation of a simple pendulum is directly proportional to the square root of its effective length (L).

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