Flag Engineering Entrance Exams> Time period of simple pendulum of length ...
question mark

Time period of simple pendulum of length l and a place where acceleration due to gravity is g is T. what is the period of a simple pendulum of the same length at a place where the acceleration due to gravity is 1.029 is, (a) T (b) 1.02 T (c) 0.99 T (d) 1.01 T

sumit kumar , 11 Years ago
Grade Upto college level
anser 2 Answers
Saurabh Koranglekar
Dear student

The Time period = 2pi*(sqrt (l/g))

Now we can calculate the needful

Regards
Last Activity: 5 Years ago
Vikas TU
When acceleration due to gravity (g) is constant, the time period (T) of oscillation of a simple pendulum is directly proportional to the square root of its effective length (L).
Last Activity: 5 Years ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments



question mark
Hello,
 
Can we learn and prepare for MHT-CET online ?
engineering entrance exams
1 Answer Available

Last Activity: 4 Years ago