Three black bodies A, B and C in the form of cubes of sides in the ratio of 3: 4: 5 are kept at the same high temperature. The ratio of the quantity of heat lost per second by A, B and C will be
(a) 27: 64: 125
(b) 5: 4: 3
(c) 9: 16: 25
(d) 25: 16: 9

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Saurabh Koranglekar · Answer

Vikas TU · Answer

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Three black bodies A, B and C in the form of cubes of sides in the ratio of 3: 4: 5 are kept at the same high temperature. The ratio of the quantity of heat lost per second by A, B and C will be (a) 27: 64: 125 (b) 5: 4: 3 (c) 9: 16: 25 (d) 25: 16: 9

Three black bodies A, B and C in the form of cubes of sides in the ratio of 3: 4: 5 are kept at the same high temperature. The ratio of the quantity of heat lost per second by A, B and C will be
(a) 27: 64: 125
(b) 5: 4: 3
(c) 9: 16: 25
(d) 25: 16: 9

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Three black bodies A, B and C in the form of cubes of sides in the ratio of 3: 4: 5 are kept at the same high temperature. The ratio of the quantity of heat lost per second by A, B and C will be (a) 27: 64: 125 (b) 5: 4: 3 (c) 9: 16: 25 (d) 25: 16: 9

Three black bodies A, B and C in the form of cubes of sides in the ratio of 3: 4: 5 are kept at the same high temperature. The ratio of the quantity of heat lost per second by A, B and C will be (a) 27: 64: 125 (b) 5: 4: 3 (c) 9: 16: 25 (d) 25: 16: 9

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Three black bodies A, B and C in the form of cubes of sides in the ratio of 3: 4: 5 are kept at the same high temperature. The ratio of the quantity of heat lost per second by A, B and C will be
(a) 27: 64: 125
(b) 5: 4: 3
(c) 9: 16: 25
(d) 25: 16: 9