There are four women P, Q, R, S and five men V, W, X, Y, Z in a group. We are required to form pairs each consisting of one women and one man. P is not to be paired with Z and Y must necessarily be paired with someone. In how many ways can four such pairs be formed.

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Vikas TU · Answer

Dear student First Fix Y with Every Men P,Q,R,S now there wil be 4 case with each man 1)P with Y for QRS => 4*3*2=24 2)Q with Y for PRS => 3*3*2=18 3)R with Y for PQS => 3*3*2=18 4)S with Y for PQR => 3*3*2=18 Total = 78 Hope this helps

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There are four women P, Q, R, S and five men V, W, X, Y, Z in a group. We are required to form pairs each consisting of one women and one man. P is not to be paired with Z and Y must necessarily be paired with someone. In how many ways can four such pairs be formed.

There are four women P, Q, R, S and five men V, W, X, Y, Z in a group. We are required to form pairs each consisting of one women and one man. P is not to be paired with Z and Y must necessarily be paired with someone. In how many ways can four such pairs be formed.

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There are four women P, Q, R, S and five men V, W, X, Y, Z in a group. We are required to form pairs each consisting of one women and one man. P is not to be paired with Z and Y must necessarily be paired with someone. In how many ways can four such pairs be formed.

There are four women P, Q, R, S and five men V, W, X, Y, Z in a group. We are required to form pairs each consisting of one women and one man. P is not to be paired with Z and Y must necessarily be paired with someone. In how many ways can four such pairs be formed.

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