The value of cos2750 + cos2450 + cos2150 – cos2300 – cos2600 is
(A) 0 (B) 1 (C) 1/2 (D) 1/4

Question

The value of cos2750 + cos2450 + cos2150 – cos2300 – cos2600 is (A) 0 (B) 1 (C) 1/2 (D) 1/4

Saurabh Koranglekar · Answer

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Vikas TU · Answer

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The value of cos2750 + cos2450 + cos2150 – cos2300 – cos2600 is (A) 0 (B) 1 (C) 1/2 (D) 1/4

The value of cos2750 + cos2450 + cos2150 – cos2300 – cos2600 is
(A) 0 (B) 1 (C) 1/2 (D) 1/4

2 Answers

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The value of cos2750 + cos2450 + cos2150 – cos2300 – cos2600 is (A) 0 (B) 1 (C) 1/2 (D) 1/4

The value of cos2750 + cos2450 + cos2150 – cos2300 – cos2600 is (A) 0 (B) 1 (C) 1/2 (D) 1/4

2 Answers

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The value of cos2750 + cos2450 + cos2150 – cos2300 – cos2600 is
(A) 0 (B) 1 (C) 1/2 (D) 1/4