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The total energy of rolling ring of mass ‘m’ and radius ‘R’ (a) 3/2 mv^2 (b) 1/2 mv^2 (c) mv^2 (d) 5/2 mv^2

The total energy of rolling ring of mass ‘m’ and radius ‘R’

(a) 3/2 mv^2 (b) 1/2 mv^2

(c) mv^2 (d) 5/2 mv^2

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1 Answers

Shrugs Shivalkar
19 Points
4 years ago
Total energy of a rolling ring of mass m, and radius R is 3/2mv^2. Since the ring is performing translation motion and also rotation motion , the linear momentum and rotation momentum of a ring if we equate we get the answer as 3/2mv^2

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